node = ['160', 'd6', '1'] t5 = '0' * (3 - len(node[-3])) + node[-3] t4 = node[-2][0] + '0' * (4 - len(node[-2])) + node[-2][1:] print t5, t4
posted on 2011-08-11 11:41 Cheney Shen 阅读(283) 评论(0) 编辑 收藏 举报
