poj3281

最大流

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#include <iostream>
#include
<cstdlib>
#include
<cstring>
#include
<cstdio>
using namespace std;

#define maxn 105
#define N maxn * 4
#define E N * N * 2
#define inf 0x3f3f3f3f

struct edge
{
int x, y, nxt;
int c;
} bf[E];

int ne, head[N], cur[N], ps[N], dep[N];
int n, f, d;

void addedge(int x, int y, int c)
{
bf[ne].x
= x;
bf[ne].y
= y;
bf[ne].c
= c;
bf[ne].nxt
= head[x];
head[x]
= ne++;
bf[ne].x
= y;
bf[ne].y
= x;
bf[ne].c
= 0;
bf[ne].nxt
= head[y];
head[y]
= ne++;
}

int flow(int n, int s, int t)
{
int tr, res = 0;
int i, j, k, f, r, top;
while (1)
{
memset(dep,
-1, n * sizeof(int));
for (f = dep[ps[0] = s] = 0, r = 1; f != r;)
for (i = ps[f++], j = head[i]; j; j = bf[j].nxt)
{
if (bf[j].c && -1 == dep[k = bf[j].y])
{
dep[k]
= dep[i] + 1;
ps[r
++] = k;
if (k == t)
{
f
= r;
break;
}
}
}
if (-1 == dep[t])
break;

memcpy(cur, head, n
* sizeof(int));
for (i = s, top = 0;;)
{
if (i == t)
{
for (k = 0, tr = inf; k < top; ++k)
if (bf[ps[k]].c < tr)
tr
= bf[ps[f = k]].c;
for (k = 0; k < top; ++k)
bf[ps[k]].c
-= tr, bf[ps[k] ^ 1].c += tr;
res
+= tr;
i
= bf[ps[top = f]].x;
}
for (j = cur[i]; cur[i]; j = cur[i] = bf[cur[i]].nxt)
if (bf[j].c && dep[i] + 1 == dep[bf[j].y])
break;
if (cur[i])
{
ps[top
++] = cur[i];
i
= bf[cur[i]].y;
}
else
{
if (0 == top)
break;
dep[i]
= -1;
i
= bf[ps[--top]].x;
}
}
}
return res;
}

int food(int a)
{
return a + 1;
}

int drink(int a)
{
return a + 1 + n * 2 + f;
}

int cowf(int a)
{
return a + 2 + f;
}

int cowd(int a)
{
return a + 2 + f + n;
}

int main()
{
//freopen("t.txt", "r", stdin);
scanf("%d%d%d", &n, &f, &d);
int s = 0;
int t = 1;
ne
= 2;
memset(head,
0, sizeof(head));
for (int i = 0; i < n; i++)
{
int a, b;
scanf(
"%d%d", &a, &b);
for (int j = 0; j < a; j++)
{
int x;
scanf(
"%d", &x);
addedge(food(x), cowf(i),
1);
}
for (int j = 0; j < b; j++)
{
int x;
scanf(
"%d", &x);
addedge(cowd(i), drink(x),
1);
}
addedge(cowf(i), cowd(i),
1);
}
for (int i = 1; i <= f; i++)
addedge(s, food(i),
1);
for (int i = 1; i <= d; i++)
addedge(drink(i), t,
1);
printf(
"%d\n", flow(n * 2 + f + d + 2, s, t));
return 0;
}
posted @ 2011-09-17 20:55  金海峰  阅读(464)  评论(0编辑  收藏  举报