poj1404

动态规划

注意多解的情况

View Code
#include <iostream>
#include
<cstdlib>
#include
<cstring>
#include
<cstdio>
using namespace std;

#define maxn 100

long long value[maxn];
char key[maxn], letter[maxn];
long long f[maxn][maxn];
int from[maxn][maxn];
int l, k;
int num[maxn];
long long sum[maxn];

void input()
{
scanf(
"%d%d", &k, &l);
scanf(
"%s", key + 1);
scanf(
"%s", letter + 1);
for (int i = 1; i <= l; i++)
scanf(
"%lld", &value[i]);
}

void work()
{
memset(from,
0, sizeof(from));
memset(f,
0, sizeof(f));
sum[
0] = 0;
long long temp;
for (int i = 1; i <= l; i++)
sum[i]
= sum[i - 1] + value[i];
for (int i = 1; i <= l; i++)
{
f[
0][i] = 1;
f[
0][i] <<= 60;
}
for (int i = 1; i <= k; i++)
{
for (int j = i; j <= l; j++)
{
temp
= 0;
f[i][j]
= 1;
f[i][j]
<<= 60;
for (int m = j - 1; m >= i - 1; m--)
{
temp
+= sum[j] - sum[m];
if (f[i][j] >= f[i - 1][m] + temp)
{
f[i][j]
= f[i - 1][m] + temp;
from[i][j]
= m;
}
}
}
}
}

void print()
{
int j = l;
for (int i = k; i > 0; i--)
{
num[i]
= j - from[i][j];
j
= from[i][j];
}
num[
0] = 0;
for (int i = 1; i <= k; i++)
num[i]
= num[i] + num[i - 1];
j
= 1;
for (int i = 1; i <= k; i++)
{
putchar(key[i]);
putchar(
':');
putchar(
' ');
while (j <= num[i])
{
putchar(letter[j]);
j
++;
}
putchar(
'\n');
}
putchar(
'\n');
}

int main()
{
//freopen("t.txt", "r", stdin);
int t;
scanf(
"%d", &t);
for (int i = 0; i < t; i++)
{
printf(
"Keypad #%d:\n", i + 1);
input();
work();
print();
}
return 0;
}

  

posted @ 2011-08-31 19:18  金海峰  阅读(171)  评论(0编辑  收藏  举报