poj2174

位操作

简单题

View Code
#include <iostream>
#include
<cstdio>
#include
<cstdlib>
#include
<cstring>
using namespace std;

#define maxn 50000

int ak[maxn], bk[maxn], b[maxn], k[maxn];
char st[maxn];
int n;

int value(char ch)
{
return ch >= '0' && ch <= '9' ? ch - '0' : ch - 'A' + 10;
}

void make(char *st, int f[])
{
int len = strlen(st);
for (int i = 0; i < len; i++)
{
if (i & 1)
f[i
>> 1] += value(st[i]);
else
f[i
>> 1] = value(st[i]) << 4;
}
}

int main()
{
//freopen("t.txt", "r", stdin);
scanf("%s", st);
n
= strlen(st) / 2;
make(st, ak);
scanf(
"%s", st);
make(st, bk);
b[
0] = 32;
for (int i = 0; i < n; i++)
{
k[i]
= b[i] ^ bk[i];
b[i
+ 1] = k[i] ^ ak[i];
}
k[n]
= b[n] ^ bk[n];
for (int i = 0; i < n + 1; i++)
printf(
"%02X", k[i]);
putchar(
'\n');
return 0;
}
posted @ 2011-07-31 16:03  金海峰  阅读(229)  评论(0编辑  收藏  举报