poj2410

简单题

View Code
#include <iostream>
#include
<cstdlib>
#include
<cstring>
#include
<cstdio>
#include
<cmath>
using namespace std;

int main()
{
//freopen("D:\\t.txt", "r", stdin);
int n;
scanf(
"%d", &n);
int m = floor(sqrt(n * 2));
int ans = 0;
for (int i = 1; i <= m; i++)
{
if (i % 2 == 0 && n % (i / 2) == 0 && n / (i / 2) % 2 == 1)
ans
++;
if (i % 2 == 1 && n % i == 0)
ans
++;
}
printf(
"%d\n", ans);
return 0;
}
posted @ 2011-04-30 15:32  金海峰  阅读(142)  评论(0编辑  收藏  举报