摘要: given a 2-d matrix with 0 or 1 values largest square of all 1's dynamic programming, dp[i][j] = 1 + min{dp[i-1][j], dp[i][j-1], dp[i-1][j-1]} if m[i][ 阅读全文
posted @ 2017-05-07 17:14 qsort 阅读(350) 评论(0) 推荐(1) 编辑