摘要: Random random = new Random(); for (int i = 0; i < 30; i++) { int[] a = new int[30]; int[] c = new int[30]; a[i] = random.Next(0, 100); c[i] = random.N 阅读全文
posted @ 2018-10-08 17:52 七越 阅读(520) 评论(0) 推荐(0)