摘要: Conclusion \[ C_{N}^{M} \bmod P=C_{ \left \lfloor N/P \right \rfloor}^{\left \lfloor M/P \right \rfloor} \times C_{ N \bmod P}^{M \bmod P} \bmod P (P是 阅读全文
posted @ 2021-07-19 19:34 OIer_Albedo 阅读(34) 评论(0) 推荐(1)