2019年8月7日

摘要: select a.Date from ( select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date from (select 0 as a union all select 1 union all select 阅读全文
posted @ 2019-08-07 17:49 小玲-ling 阅读(2354) 评论(0) 推荐(0)

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