数据库记录转换成json格式

<?php
/
1.在company数据user表中取出10条数据,保存为数组
2.在将数组转化为json格式,传递给js
3.用json解析器将传递过来的json字符串转化为json对象,
4.用document.write输出语句打印在页面上
*/

 

$conn = mysql_connect(“localhost”,”root”,”root”);   //连接数据库
mysql_query(“set names utf8″);                       //设置编码
mysql_select_db(“company”,$conn);                   //选择库

$sql = “select * from user limit 10″;               //在user表中查询10条数据
$res = mysql_query($sql);                           //执行sql语句
$arr = array();

while($row = mysql_fetch_array($res,MYSQL_ASSOC)){   //查询出来sql
$arr[] = $row;                                   //将查询出来的结果赋给数组$arr
}

$str = json_encode($arr);                           //将数组转化为json格式的字符串

?>

<script src=”json_parse.js”></script>                   <!– 引入json解析器 –>
<table>
<tr>
<th>uid</th><th>用户名</th><th>性别</th><th>email</th>
</tr>
<script>
var jsonString = ‘<?php echo $str;?>’;          //传递php中的数据给js

//document.write(jsonString);

var jsonObject = json_parse(jsonString);           //将json字符串转化为js中的json对象

for(var i = 0; i < jsonObject.length; i++){           //for循环打印
document.write(“<tr>”);
document.write(“<td>”,jsonObject[i].uid,”</td>”);
document.write(“<td>”,jsonObject[i].username,”</td>”);
document.write(“<td>”,jsonObject[i].sex,”</td>”);
document.write(“<td>”,jsonObject[i].email,”</td>”);
document.write(“</tr>”);
}
</script>
</table>

posted on 2013-05-01 22:17  疯狂的石头陈  阅读(1304)  评论(0编辑  收藏  举报

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