摘要:
核心代码:?DataSet ds = dBll.GetList("ID=" + ID);?string docName = "a.doc";//文件名,?byte[] file = (byte[])ds.Tables[0].Rows[0]["FContent"]; // "FContent"类型为imagestring Type = checktype(docName);Response.AddHeader("Content-Disposition", "attachment;file 阅读全文
posted @ 2013-08-15 09:22
KKKK天才
阅读(320)
评论(0)
推荐(0)
浙公网安备 33010602011771号