摘要: 2.哲学家吃面问题 semaphore fork[5]; for(int i=0; i<5;i++) fork[i]=1; cobegin process philosopher_i( ){ while(ture){ think( ); P(fork[i]); P(fork[(i+10%5]); e 阅读全文
posted @ 2019-05-06 21:17 胡振江 阅读(157) 评论(0) 推荐(0) 编辑