摘要: class Solution { public: vector<int> twoSum(vector<int>& nums, int target) { unordered_map<int, int> map; for (int i = 0; i < nums.size(); i ++) { aut 阅读全文
posted @ 2022-09-05 17:36 hjy94wo 阅读(16) 评论(0) 推荐(0)
摘要: class Solution { public: int getSum(int n) { int sum = 0; while (n) { sum += (n % 10) * (n % 10); n /= 10; } return sum; } bool isHappy(int n) { unord 阅读全文
posted @ 2022-09-05 17:15 hjy94wo 阅读(16) 评论(0) 推荐(0)
摘要: class Solution { public: bool record[1010]; vector<int> res; vector<int> intersection(vector<int>& nums1, vector<int>& nums2) { unordered_set<int> set 阅读全文
posted @ 2022-09-05 16:13 hjy94wo 阅读(20) 评论(0) 推荐(0)
摘要: class Solution { public: bool isAnagram(string s, string t) { if (s.size() != t.size()) return false; sort(s.begin(), s.end()); sort(t.begin(), t.end( 阅读全文
posted @ 2022-09-05 15:47 hjy94wo 阅读(8) 评论(0) 推荐(0)
摘要: class Solution { public: vector<vector<int>> res; vector<int> path; int used[10]; void dfs(vector<int>& nums) { if (path.size() == nums.size()) { res. 阅读全文
posted @ 2022-09-05 14:57 hjy94wo 阅读(14) 评论(0) 推荐(0)
摘要: class Solution { public: vector<vector<int>> res; vector<int> path; bool used[10]; void dfs(vector<int>& nums) { if (path.size() == nums.size()) { res 阅读全文
posted @ 2022-09-05 14:44 hjy94wo 阅读(18) 评论(0) 推荐(0)
摘要: class Solution { public: vector<vector<int>> res; vector<int> path; int num = -101; void dfs(int start, vector<int>& nums) { if (path.size() > 1) { re 阅读全文
posted @ 2022-09-05 10:51 hjy94wo 阅读(7) 评论(0) 推荐(0)
摘要: class Solution { public: vector<vector<int>> res; vector<int> path; void dfs(int start, vector<int>& nums) { res.push_back(path); for (int i = start; 阅读全文
posted @ 2022-09-05 10:07 hjy94wo 阅读(13) 评论(0) 推荐(0)
摘要: class Solution { public: vector<vector<int>> res; vector<int> path; void dfs(int start, vector<int>& nums) { res.push_back(path); for (int i = start; 阅读全文
posted @ 2022-09-05 08:45 hjy94wo 阅读(19) 评论(0) 推荐(0)
摘要: class Solution { public: vector<string> res; int pointNum; bool isValid(string s, int begin, int end) { if (begin > end) return false; //防止在最后末尾插入. if 阅读全文
posted @ 2022-09-04 15:54 hjy94wo 阅读(27) 评论(0) 推荐(0)