用Collections.sort方法对现有的List重新进行排序


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重新将relList里的数据按照sequenceNo和subName进行排序 Collections.sort(relList, new Comparator<Object>() { @Override public int compare(Object obj1, Object obj2) {   CpPlanSubRel rel1 = (CpPlanSubRel) obj1;   CpPlanSubRel rel2 = (CpPlanSubRel) obj2;   // 首先比较序号,如果序号(sequenceNo)相同,则比较科目名字(subName)   int flag = rel1.getCpSubject().getSequenceNo().compareTo(rel2.getCpSubject().getSequenceNo());   if (flag == 0)   return rel1.getCpSubject().getSubName().compareTo(rel2.getCpSubject().getSubName());   else      return flag; } });
posted @ 2012-11-29 18:05  Caliven  阅读(270)  评论(0编辑  收藏  举报