摘要: task4 源代码 #include <stdio.h> #include <ctype.h> int main() { char ch; FILE *fp; int n=0; fp = fopen("data4.txt", "r"); if(fp == NULL) { printf("fail t 阅读全文
posted @ 2023-06-11 12:56 战①柔 阅读(11) 评论(0) 推荐(0)