摘要: 1 "; }elseif($pageTotal".$i.""; } }else{ $pagePrev=$pageNow-ceil($lstPage/2); $pageNext=$pageNow+ceil($lstPage/2); if($pagePrev$pageTotal-1){$pageNext=$pageTotal-1;} //倒数第二页结束 //First and Last $pageNow>1&&$page.=" "; $page.="1.. "; $pageA=$pageNow-2 阅读全文
posted @ 2012-09-27 11:14 网络剑客 阅读(180) 评论(0) 推荐(0)