Kaitou Kid - The Phantom Thief (1)（字符串，简单）

Kaitou Kid - The Phantom Thief (1)

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1498    Accepted Submission(s): 666

Problem Description

Do you know Kaitou Kid? In the legend, Kaitou Kid is a master of disguise, and can take on the voice and form of anyone. He is not an evil person, but he is on the wrong side of the law. He's the very elusive phantom thief who never miss his prey although he always uses word puzzles to announce his targets before action.



You are the leader of a museum. Recently, you get several priceless jewels and plan to hold an exhibition. But at the moment, you receive Kid's word puzzle... Fortunately, It seems Kid doesn’t want to trouble you, and his puzzle is very easy. Just a few minutes, You have found the way to solve the puzzle:

(1) change 1 to 'A', 2 TO 'B',..,26 TO 'Z'
(2) change '#' to a blank
(3) ignore the '-' symbol, it just used to separate the numbers in the puzzle

 

 

Input

The first line of the input contains an integer C which means the number of test cases. Then C lines follow. Each line is a sentence of Kid’s word puzzle which is consisted of '0' ~ '9' , '-' and '#'. The length of each sentence is no longer than 10000.

 

 

Output

For each case, output the translated text.

 

 

Sample Input

4 9#23-9-12-12#19-20-5-1-12#1-20#12-5-1-19-20#15-14-5#10-5-23-5-12 1-14-4#12-5-1-22-5#20-8-5#13-21-19-5-21-13#9-14#20#13-9-14-21-20-5-19 1-6-20-5-18#20-8-5#15-16-5-14-9-14-7#15-6#20-8-5#5-24-8-9-2-9-20-9-15-14 7-15-15-4#12-21-3-11

 

 

Sample Output

I WILL STEAL AT LEAST ONE JEWEL AND LEAVE THE MUSEUM IN T MINUTES AFTER THE OPENING OF THE EXHIBITION GOOD LUCK

 

 

Author

LL

 

 

Source

2008杭电集训队选拔赛

 

 

Recommend

wangye

 

#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstring>
#include <algorithm>
#define LL long long
#define maxint 2147483647
#define maxll 9223372036854775807
#define dg cout << "Here!" << endl;
using namespace std;

int main()
{
    int C, i, len;
    char s[10001], ch;
    scanf("%d", &C);
    while(C--)
    {
        scanf("%s", s);
        len = strlen(s);
        for(i = 0; i < len; i++)
        {
            if(s[i] >= '0' && s[i] <= '9')
            {
                if(s[i+1] == '-' || s[i+1] == '\0')
                {
                    //ch = s[i] + 'A' - '1';
                    putchar(s[i] + 'A' - '1');
                    i++;
                }
                else if(s[i+1] >= '0' && s[i+1] <='9')
                {
                    //ch = (s[i] - '0')*10 + s[i+1] - '0' + 'A' - 1;
                    putchar((s[i] - '0')*10 + s[i+1] - '0' + 'A' - 1);
                    i++;
                }
                else putchar(s[i] + 'A' - '1');
            }
            else if(s[i] == '#')
                putchar(' ');

        }
        puts("");
    }
    return 0;
}