摘要:
1 assume cs:code,ss:stack,ds:data 2 stack segment 3 db 128 dup (0) 4 stack ends 5 6 data segment 7 dw 0,0 8 data ends 9 10 code segment11 start:12 mov ax,stack13 mov ss,ax14 mov sp,12815 16 mov ax,data17 mov ds,ax18 19 mov ax,020 mov es,ax21 22 p... 阅读全文
posted @ 2013-04-28 17:08
CrackKay
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