Hibernate - 查询部分字段

使用Hibernate 只查詢部分字段,有三种字现方式:

 

第一种是使用高级查询DetachedCriteria实现,代碼如下

String alias = "user_"; //查詢時的table別名

DetachedCriteria dc = DetachedCriteria.forClass(User.class,alias);

ProjectionList pList = Projections.projectionList();

pList.add(Projections.property(alias + "." + "id").as("id"));

pList.add(Projections.property(alias + "." + "name").as("name"));

pList.add(Projections.property(alias + "." + "age").as("age"));

pList.add(Projections.property(alias + "." + "sex").as("sex"));

dc.setProjection(pList);

dc.setResultTransformer(Transformers.aliasToBean(User.class));

resultList = memberService.findByDetached(dc).size();

 

第二种方式是通过HQL语句new POJO()实现,方法如下:

package com.domain;

public class Link {

    private String id;

    private String name;

    private String url;

    private Integer index;

    public Link(){}

    //因为:String hql = "select new Link(id,name) from Link";

//所以必须要有接受2个参数的构造函数

    public Link(String id,String name){

       this.id = id;

       this.name = name;

    }

    public String getName() {

       return name;

    }

    public void setName(String name) {

       this.name = name;

    }

    public String getUrl() {

       return url;

    }

    public void setUrl(String url) {

       this.url = url;

    }

}

 

 

通過HQL语句查询

String hql = "select new Link(id,name) from Link";     

Query query = session.createQuery(hql);

//默认查询出来的list里存放的是一个Object对象,但是在这里list里存放的不再是默认的Object对象了,而是Link对象了

List<Link> links = query.list();

for(Link link : links){

    String id = link.getId();

    String name = link.getName();

    System.out.println(id + " : " + name);

}

 

第三种方式是通过HQL语句实现,类似SQL,方法如下:

String hql = "select id,name from Link";     

Query query = session.createQuery(hql);

//默认查询出来的list里存放的是一个Object数组,还需要转换成对应的javaBean

List<Object[]> links = query.list();

for(Object[] link : links){

    String id = link[0];

    String name = link[1];

    System.out.println(id + " : " + name);

}

 

 

posted @ 2012-08-06 17:00  戴眼镜的码农  阅读(2225)  评论(0编辑  收藏  举报