摘要: Acm练习(六)1.//1的个数#includeusing namespace std;int jj(int n){ int count=0; for(int l=n;l>0;l=l/2) { if(l%2 !=0 ) { count=count+1; } } r... 阅读全文
posted @ 2015-04-05 14:30 BugsTerminator 阅读(173) 评论(0) 推荐(0)