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利用内置lambda函数给dict排序

# sort.py
#
-*- coding: gbk -*
# 这个类用来演示如何对自定义对象进行排序
class Sortobj:
a
= 0
b
= ''
def __init__(self, a, b):
self.a
= a
self.b
= b
def printab(self):
print self.a, self.b

# 演示对字符串列表进行排序
samplelist_str
= ['blue','allen','sophia','keen']
print samplelist_str
samplelist_str.sort()
print samplelist_str

print
'\n'

# 演示对整型数进行排序
samplelist_int
= [34,23,2,2333,45]
print samplelist_int
samplelist_int.sort()
print samplelist_int

print
'\n'

# 演示对字典数据进行排序
sampledict_str
= {'blue':'5555@sina.com',
'allen':'222@163.com',
'sophia':'4444@gmail.com',
'ceen':'blue@263.net'}
print sampledict_str
# 按照key进行排序
print sorted(sampledict_str.items(), key
=lambda d: d[0])
# 按照value进行排序
print sorted(sampledict_str.items(), key
=lambda d: d[1])

# 构建用于排序的类实例
obja
= Sortobj(343, 'keen')
objb
= Sortobj(56, 'blue')
objc
= Sortobj(2, 'aba')
objd
= Sortobj(89, 'iiii')

print
'\n'

samplelist_obj
= [obja, objb, objc, objd]
# 实例对象排序前
for obj in samplelist_obj:
obj.printab()
print
'\n'
# 按照对象的a属性进行排序
samplelist_obj.sort(lambda x,y: cmp(x.a, y.a))
for obj in samplelist_obj:
obj.printab()
print
'\n'
# 按照对象的b属性进行排序
samplelist_obj.sort(lambda x,y: cmp(x.b, y.b))
for obj in samplelist_obj:
obj.printab()

程序转自:http://www.sqlite.com.cn/MySqlite/11/434.Html

posted @ 2011-04-27 17:26  runfox545  阅读(719)  评论(0编辑  收藏  举报
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