摘要:
/* 调用pow求幂 */#include#includeint main(void){ int i,n; double power; printf("Enter n:"); scanf("%d",&n); for(i=0;iint main(void){ int num1,num2,a,b,c,d,e; a=num1+num2; b=num1-num2; c=num1*num2; d=num1/num2; e=num1%num2; printf("a=%d,b=%d,c=%d,d=%d,e=%d\n",a,b,c,d,e.. 阅读全文
posted @ 2013-10-19 21:16
mo77
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摘要:
#includeint main(void){ int i,n; double r,h,x; double cylinder(double r,double h); printf("Enter n:"); scanf("%d",&n); for(i=1;i0)||(h>0)) { x=cylinder(r,h); printf("x=%.3f\n",x); } else{ printf(Wrong!make it again \n); } ... 阅读全文
posted @ 2013-10-19 21:03
mo77
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