USACO Shaping Regions(离散化)

　　记录一下我一直很怕做的一道离散化题。都卡了大半个月了，今天终于过了。这种离散化的题就一个恶心，不然早就啃过去了。
代码如下：
View Code
  1 /*
  2 ID: lyon.ly1
  3 LANG: C++
  4 TASK: rect1
  5 */
  6 
  7 #include <cstring>
  8 #include <iomanip>
  9 #include <cmath>
 10 #include <cstdio>
 11 #include <iostream>
 12 #include <algorithm>
 13 #include <vector>
 14 #include <string>
 15 #include <queue>
 16 #include <ctime>
 17 #include <map>
 18 #include <set>
 19 
 20 using namespace std;
 21 
 22 #define PB push_back
 23 #define FI first
 24 #define SE second
 25 #define MPR make_pair
 26 #define REP(i, n) for (int i = 0; i < n; i++)
 27 #define REP_1(i, n) for (int i = 1; i <= n; i++)
 28 #define FORI(i, a, b) for (int i = a; i < b; i++)
 29 #define FORD(i, a, b) for (int i = a; i > b; i--)
 30 #define _clr(x) memset(x, 0, sizeof(x))
 31 #define _rst(x) memset(x, -1, sizeof(x))
 32 
 33 typedef long long LL;
 34 typedef pair<int, int> PII;
 35 typedef vector<LL> VLL;
 36 typedef vector<PII> VPII;
 37 typedef vector<int> VI;
 38 typedef vector<double> VDBL;
 39 const int N = 2505;
 40 const int hashMod = 1e6 + 5;
 41 const int inf = 0x55555555;
 42 const double eps = 1e-8;
 43 const LL linf = 0x5555555555555555ll;
 44 const double finf = 1e50;
 45 const double pi = acos(-1.0);
 46 const int mod = 1e9 + 7;
 47 
 48 FILE *fin = fopen("rect1.in", "r");
 49 FILE *fout = fopen("rect1.out", "w");
 50 
 51 struct Rect {
 52     int x1, y1, x2, y2, cl;
 53     Rect(int a = 0, int b = 0, int c = 0, int d = 0, int e = 0) {
 54         if (a > c) swap(a, c);
 55         if (b > d) swap(b, d);
 56         x1 = a, y1 = b, x2 = c, y2 = d, cl = e;
 57     }
 58 } ;
 59 
 60 queue<Rect> Q;
 61 int clr[N];
 62 
 63 bool belong(int x1, int y1, int x2, int y2, Rect &x) {
 64     return x.x1 <= x1 && x2 <= x.x2 && x.y1 <= y1 && y2 <= x.y2;
 65 }
 66 
 67 void insert(Rect x) {
 68     int sz = Q.size();
 69     int X[5], Y[5];
 70     while (sz--) {
 71         Rect tmp = Q.front();
 72 //        printf("!!!          %d %d %d %d %d\n", tmp.x1, tmp.y1, tmp.x2, tmp.y2, tmp.cl);
 73         Q.pop();
 74         if (tmp.x2 <= x.x1 || x.x2 <= tmp.x1) { Q.push(tmp); continue;}
 75         if (tmp.y2 <= x.y1 || x.y2 <= tmp.y1) { Q.push(tmp); continue;}
 76 //        puts("~~~~~~~~~~~~~~~");
 77 //        printf("rect %d %d %d %d %d\n", tmp.x1, tmp.y1, tmp.x2, tmp.y2, tmp.cl);
 78         X[0] = x.x1, X[1] = x.x2;
 79         Y[0] = x.y1, Y[1] = x.y2;
 80         X[2] = tmp.x1, X[3] = tmp.x2;
 81         Y[2] = tmp.y1, Y[3] = tmp.y2;
 82         sort(X, X + 4);
 83         sort(Y, Y + 4);
 84 //        REP(i, 4) {
 85 //            printf("x %d y %d\n", X[i], Y[i]);
 86 //        }
 87         REP(i, 3) {
 88             if (X[i] == X[i + 1]) continue;
 89             REP(j, 3) {
 90                 if (Y[j] == Y[j + 1]) continue;
 91                 if (belong(X[i], Y[j], X[i + 1], Y[j + 1], tmp) && !belong(X[i], Y[j], X[i + 1], Y[j + 1], x)) {
 92                     Q.push(Rect(X[i], Y[j], X[i + 1], Y[j + 1], tmp.cl));
 93 //                    printf("pb %d %d %d %d %d\n", X[i], Y[j], X[i + 1], Y[j + 1], tmp.cl);
 94                 }
 95             }
 96         }
 97 //        puts("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~");
 98     }
 99     Q.push(x);
100 }
101 
102 int main() {
103     int a, b, c, d, e, n;
104 //    freopen("in", "r", stdin);
105     while (~fscanf(fin, "%d%d%d", &a, &b, &n)) {
106         while (Q.size()) Q.pop();
107         _clr(clr);
108         Q.push(Rect(0, 0, a, b, 1));
109         while (n--) {
110             fscanf(fin, "%d%d%d%d%d", &a, &b, &c, &d, &e);
111 //            printf("Rect ~~~~~~~~~~~~~~~~~~     %d %d %d %d %d\n", a, b, c, d, e);
112             insert(Rect(a, b, c, d, e));
113         }
114         while (Q.size()) {
115             Rect tmp = Q.front();
116 //            printf("%d %d %d %d %d\n", tmp.x1, tmp.y1, tmp.x2, tmp.y2, tmp.cl);
117             Q.pop();
118             clr[tmp.cl] += (tmp.x2 - tmp.x1) * (tmp.y2 - tmp.y1);
119         }
120         REP(i, N) {
121             if (clr[i]) {
122                 fprintf(fout, "%d %d\n", i, clr[i]);
123             }
124         }
125     }
126     return 0;
127 }
——written by Lyon
posted @ 2012-12-13 12:45 LyonLys 阅读(170) 评论(0) 收藏举报
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