02 2021 档案

摘要:$$\begin{eqnarray}&c[k] = \sum_{i}^{n}a[i]b[i-k] \\&c[k] = \sum_{i}^{n}a[n-i]b[i-k] (倒序保存a) \\&c[n-k]= \sum_{i}^{n}a[n-i]b[i-k] (倒序保存c) \\&通过卷积 o (nlo 阅读全文
posted @ 2021-02-25 17:04 HKHbest 阅读(82) 评论(0) 推荐(0)

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