HDU-1166-敌兵布阵(线段树)(树状数组)

  • 线段树(kuangbin本题链接
    #include "bits/stdc++.h"
    using namespace std;
    const int MAXN = 50010;
    struct Node {
        int l, r;
        int sum;
    } segTree[MAXN * 4];
    void build(int i, int l, int r) {
        segTree[i].l = l;
        segTree[i].r = r;
        if (l == r) {
            scanf("%d", &segTree[i].sum);
            return;
        }
        int mid = l + r >> 1;
        build(i << 1, l, mid);
        build(i << 1 | 1, mid + 1, r);
        segTree[i].sum = segTree[i << 1].sum + segTree[i << 1 | 1].sum;
    }
    void add(int i, int k, int v) {
        segTree[i].sum += v;
        if (segTree[i].l == segTree[i].r) return;
        int mid = segTree[i].l + segTree[i].r >> 1;
        if (k <= mid) add(i << 1, k, v);
        else add(i << 1 | 1, k, v);
    }
    int query(int i, int l, int r) {
        if (segTree[i].l == l && segTree[i].r == r) return segTree[i].sum;
        int mid = segTree[i].l + segTree[i].r >> 1;
        if (r <= mid) return query(i << 1, l, r);
        else if (l > mid) return query(i << 1 | 1, l, r);
        else return query(i << 1, l, mid) + query(i << 1 | 1, mid + 1, r);
    }
    int main() {
        int t, n; char op[10];
        scanf("%d", &t);
        for (int ca = 1; ca <= t; ca++) {
            printf("Case %d:\n", ca);
            scanf("%d", &n);
            build(1, 1, n);
            int x, y;
            while (scanf("%s", op) && op[0] != 'E') {
                scanf("%d%d", &x, &y);
                if (op[0] == 'Q') printf("%d\n", query(1, x, y));
                else if (op[0] == 'A') add(1, x, y);
                else add(1, x, -y);
            }
        }
        return 0;
    }

    修改自2019年6月6日,删除了原先的线段树代码,原先不喜欢用结构体定义线段树的节点,现在感觉到用结构体代码清晰一点。模仿的kuangbin模板。

  • 树状数组
    #include"cstdio"
    #include"cstring"
    using namespace std;
    int tree[50005],N,x,y;
    //用来求x二进制码从右往左数第一个1所在位的值
    int lowbit(int x){
        return x&-x;
    }
    void Add(int x){
        while(x<=N){
            tree[x]+=y;
            x+=lowbit(x);
        }
    }
    int Query(int x){
        int ans=0;
        while(x){
            ans+=tree[x];
            x-=lowbit(x);
        }
        return ans;
    }
    int main(){
        int T;char s[10];
        scanf("%d",&T);
        for(int k=1;k<=T;k++){
            memset(tree,0,sizeof(tree));
            scanf("%d",&N);
            for(int i=1;i<=N;i++){
                scanf("%d",&y);
                Add(i);
            }
            printf("Case %d:\n",k);
            while(scanf("%s",s)&&s[0]!='E'){
                scanf("%d%d",&x,&y);
                if(s[0]=='Q')printf("%d\n",Query(y)-Query(x-1));
                else {
                    if(s[0]=='S')y=-y;
                    Add(x);
                }
            }
        }
        return 0;
    }

     

posted @ 2018-11-19 22:31  Jathon-cnblogs  阅读(195)  评论(0编辑  收藏  举报