摘要: 一、写出输出结果 #include<stdio.h> int main(){ int a[3]; a[0] = 0; a[1] = 1; a[2] = 2; int *p,*q; p = a; q = &a[2]; int c = a[q-p]; printf("value c = %d/n",c+ 阅读全文
posted @ 2016-03-01 10:10 AndyJee 阅读(796) 评论(0) 推荐(0) 编辑