摘要: v = "alex"v = v.replace("l","el")print(v) li = [11,22,33,44,55]li[0] = 00print(li) #补充:错误,字符串创建后不可更改li ="alex"li[0]li[0] = "E" 阅读全文
posted @ 2019-09-24 21:22 别看我看路 阅读(138) 评论(0) 推荐(0)
摘要: #通过嵌套索引li = [1,12,9,"age","alex",["12","fsdfsf"],"56456"]print(li[5][1][0]) #既有数字又有字符串,需要自己写for循环s = ""for i in li: s = s + str(i)print(s) #直接使用字符串的join方法:列表中的元素只有字符串ni = ["fff","122"]v =... 阅读全文
posted @ 2019-09-24 21:21 别看我看路 阅读(175) 评论(0) 推荐(0)
摘要: li = [1,12,9,"age","alex",["dsad"],True]#中括号括起来#分隔每个元素#列表中的元素可以是数字,字符串,列表,布尔值..所有的都能放进去#"集合",内部放置任何东西#索引取值print(li[3])#切片,切片结果也是列表print(li[1:4]) #for循环#while 循环for item in li: print(item) ... 阅读全文
posted @ 2019-09-24 21:01 别看我看路 阅读(136) 评论(0) 推荐(0)