C#将datatable生成easyui的绑定tree 的json数据格式[转载]

在用easyui控件的时候常用到他能解析的 接送数据,我们可以通过c#将我们从数据库中得到datatable转换成那样的格式,datagrid的好转换,简单的循环拼串就可以,不过 easyui绑定树的时候的接送数据格式稍有不同,比datagrid和datagridtree得到json数据要稍微复杂一些,我写了性能虽然不是很 好的,但是也能得到想要的数据!

/// <summary>
    /// 根据DataTable生成Json树结构
    /// </summary>
    /// <param name="tabel">数据源</param>
    /// <param name="idCol">ID列</param>
    /// <param name="txtCol">Text列</param>
    /// <param name="rela">关系字段</param>
    /// <param name="pId">父ID</param>
    StringBuilder result = new StringBuilder();
    StringBuilder sb = new StringBuilder();
    private void GetTreeJsonByTable(DataTable tabel, string idCol, string txtCol, string rela, object pId)
    {
        result.Append(sb.ToString());
        sb.Clear();
        if (tabel.Rows.Count > 0)
        {
            sb.Append("[");
            string filer = string.Format("{0}='{1}'", rela, pId);
            DataRow[] rows = tabel.Select(filer);
            if (rows.Length > 0)
            {
                foreach (DataRow row in rows)
                {
                    sb.Append("{\"id\":\"" + row[idCol] + "\",\"text\":\"" + row[txtCol] + "\",\"state\":\"open\"");
                    if (tabel.Select(string.Format("{0}='{1}'", rela, row[idCol])).Length > 0)
                    {
                        sb.Append(",\"children\":");
                        GetTreeJsonByTable(tabel, idCol, txtCol, rela, row[idCol]);
                        result.Append(sb.ToString());
                        sb.Clear();
                    }
                    result.Append(sb.ToString());
                    sb.Clear();
                    sb.Append("},");
                }
                sb = sb.Remove(sb.Length - 1, 1);
            }
            sb.Append("]");
            result.Append(sb.ToString());
            sb.Clear();
        }
    }

调用方法很简单,运行这个void 类型的函数,然后取result 的值就行了,

GetTreeJsonByTable(datatable, "id", "title", "pid", "0");
string content = result.ToString();

 

posted @ 2017-04-10 13:49  pilink  阅读(760)  评论(0编辑  收藏  举报