Delphi XE5 android openurl(转)

Posted on 2013-11-06 16:12  至今  阅读(1351)  评论(0编辑  收藏  举报

直接上代码:

unit OpenViewUrl;
interface // URLEncode is performed on the URL// so you need to format it   protocol://path
function OpenURL(const URL: string; const DisplayError: Boolean = False): Boolean;
implementation
uses IdURI, SysUtils, Classes, FMX.Dialogs,
{$IFDEF ANDROID}
  FMX.Helpers.Android, Androidapi.JNI.GraphicsContentViewText, Androidapi.JNI.Net, Androidapi.JNI.JavaTypes;
{$ELSE}{$IFDEF IOS}iOSapi.Foundation, FMX.Helpers.iOS;
{$ENDIF IOS}{$ENDIF ANDROID}

function OpenURL(const URL: string; const DisplayError: Boolean = False): Boolean;
{$IFDEF ANDROID}
var Intent: JIntent;
begin // There may be an issue with the geo: prefix and URLEncode.// will need to research
  Intent := TJIntent.JavaClass.init(TJIntent.JavaClass.ACTION_VIEW, TJnet_Uri.JavaClass.parse(StringToJString(TIdURI.URLEncode(URL))));
  try SharedActivity.startActivity(Intent);
    exit(true);
  except
    on e: Exception do
    begin
      if DisplayError then ShowMessage('Error: ' + e.Message);
      exit(false);
    end;
  end;
end;
{$ELSE}{$IFDEF IOS}
var NSU: NSUrl;
begin
 // iOS doesn't like spaces, so URL encode is important.
  NSU := StrToNSUrl(TIdURI.URLEncode(URL));
  if SharedApplication.canOpenURL(NSU) then
    exit(SharedApplication.openUrl(NSU))
  else
  begin
    if DisplayError then
      ShowMessage('Error: Opening "' + URL + '" not supported.');
    exit(false);
  end;
end;
{$ELSE}
begin
  raise Exception.Create('Not supported!');
end;
{$ENDIF IOS}{$ENDIF ANDROID}
end.
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