Leetcode 290 Word Pattern
Given a pattern and a string str, find if str follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str.
Examples:
- pattern =
"abba", str ="dog cat cat dog"should return true. - pattern =
"abba", str ="dog cat cat fish"should return false. - pattern =
"aaaa", str ="dog cat cat dog"should return false. - pattern =
"abba", str ="dog dog dog dog"should return false.
Notes:
You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space.
首先检验长度是否一致
然后判断每个map关系是否唯一对应
class Solution(object): def wordPattern(self, pattern, str): str = str.split(' ') if len(pattern) != len(str): return False h = {} for i in range(len(str)): if not h.has_key(pattern[i]): if str[i] not in h.values(): h[pattern[i]] = str[i] else: return False else: if h[pattern[i]] != str[i]: return False return True
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