恒生电子2012实习笔试题

 

 

 

 

 

一、不定项选择题

1、B

2、AD

3、CD

4、A

5、ACD

6、BD

7、C

8、BCD

9、C

10、AB 主键不一定能提高查找的速度

 

二、填空题

1、奇，偶

2、ls -l,ps -aux

3、

4、BABBAB

5、数据定义，数据操作，数据控制

 

三、数据库

1、

create table S(
    Sno int primary key auto_increment,
    Sname varchar(20)

);

insert into S(sname) values('he');
insert into S(sname) values('wang');

create table C(
    Cno int primary key auto_increment,
    Cname varchar(20),
    Ccredit int
);


insert into C(cname,Ccredit) values('JAVA',3);
insert into C(cname,Ccredit)  values('C',2);

Drop table if exists SC;
create table SC(
    id int primary key auto_increment,
    Sno int,
    Cno int,
    Grade int
);


insert into SC(Sno,cno,Grade) values(1,1,100);
insert into SC(Sno,cno,Grade) values(1,2,90);
insert into SC(Sno,cno,Grade) values(2,1,80);
insert into SC(Sno,cno,Grade) values(2,2,70);
insert into SC(Sno,cno,Grade,Teacher) values(3,1,80,'zhang');
insert into SC(Sno,cno,Grade,Teacher) values(3,2,70,'zhang');

1)select distinct Sname From S,SC,C where S.sno = SC.sno and c.Cno = SC.cno and
Cname='JAVA' order by Sname desc;

2)select S.Sno,Sum(Ccredit) From S,SC,C where S.sno = SC.sno and c.Cno = SC.cno

and Grade>60 group by Sno having sum(Ccredit)>80;

3)ALTER table SC ADD Teacher varchar(20) not null;

4)CREATE VIEW SCSum(sno,Ccredit) as Select S.Sno,Sum(Ccredit)  From S,SC,C

where S.sno = SC.sno and c.Cno = SC.cno group by Sno;  

5)delete from SC where sno not in(select distinct S.Sno from S);

 

四、程序设计题

package hengsheng;

public class Exe1 {
    public static void main(String[] args) {
        for(int i=123;i<330;i++){
            int a = i*2;
            int b = i*3;
            if(isok(i,a,b)){
                System.out.println(i+","+a+","+b);
            }
        }
    }
    
    /**
     * 判断三个整数中是否有重复的字符
     * @return false:有;true:否
     */
    private static boolean isok(int i,int a,int b) {
        int[] s = new int[9];
        s[0] = i%10;
        s[1] = i%100/10;
        s[2] = i/100;
        s[3] = a%10;
        s[4] = a%100/10;
        s[5] = a/100;
        s[6] = b%10;
        s[7] = b%100/10;
        s[8] = b/100;
        //判断s中是否有相同的数字
        for(int j=0;j<s.length;j++){
            for(int k=j;k<s.length;k++){
                if(j != k && s[j] == s[k])
                    return false;
            }
        }
        return true;
    }
}