面向过程编程向面向对象编程转换——比较两个长方体是否相等 

  1 #include <iostream>
  2 using namespace std;
  3 class Cube
  4 {
  5 public:
  6     void setA(int a)
  7     {
  8         m_a = a;
  9     }
 10     void setB(int b)
 11     {
 12         m_b = b;
 13     }
 14     void setC(int c)
 15     {
 16         m_c = c;
 17     }
 18     void setABC(int a, int b, int c)
 19     {
 20         m_a = a;
 21         m_b = b;
 22         m_c = c;
 23     }
 24     int getV()
 25     {
 26         m_v = m_a*m_b*m_c;
 27         return m_v;
 28     }
 29     int getA()
 30     {
 31         return m_a;
 32     }
 33     int getB()
 34     {
 35         return m_b;
 36     }
 37     int getC()
 38     {
 39         return m_c;
 40     }
 41     int judge(Cube &v1, Cube &v2)
 42     {
 43         
 44         if ((v1.getA() == v2.getA()) && (v1.getB() == v2.getB()) && (v1.getC() == v2.getC()))
 45         {
 46             return 1;
 47         }
 48         else
 49         {
 50             return 0;
 51         }
 52     }
 53     int judge(Cube &v2)//成员函数  函数重载
 54     {
 55         //此时的这个场景下的m_a是属于v1还是v2?---属于v1，谁调用属于谁
 56         if ((m_a==v2.getA())&&(m_b==v2.getB())&&m_c==v2.getC())
 57         {
 58             return 1;
 59         }
 60         else
 61         {
 62             return 0;
 63         }
 64     }
 65 
 66 private:
 67     int m_a;
 68     int m_b;
 69     int m_c;
 70     int m_s;
 71     int m_v;
 72 
 73 };
 74 
 75 //全局函数PK成员函数
 76 
 77 //全局函数
 78 int judge(Cube &v1,Cube &v2)
 79 {
 80     if ((v1.getA()==v2.getA())&&(v1.getB()==v2.getB())&&(v1.getC()==v2.getC()))
 81     {
 82         return 1;
 83     }
 84     else
 85     {
 86         return 0;
 87     }
 88 }
 89 
 90 //面向对象
 91 void main()
 92 {
 93     Cube V1, V2;
 94     V1.setABC(1, 2, 3);
 95     V2.setABC(1, 2, 4);
 96     cout << V1.getV() << endl;
 97     //
 98     int tag = V1.judge(V2);
 99     if (tag==1)
100     {
101         cout << "相等" << endl;
102     }
103     else
104     {
105         cout << "不等" << endl;
106     }
107     //V1.judge(V1);//判断v1立方体和v2立方体是否相等  通过类的成员函数
108 
109 
110     /*
111     V1.judge(V1, V2);
112     if (judge(V1, V2) == 1)
113     {
114         cout << "相等" << endl;
115     }
116     else
117     {
118         cout << "不等" << endl;
119     }
120     */
121     system("pause");
122     return;
123 }
124 
125 void main_全局函数调用面向过程()
126 {
127     Cube V1,V2;
128     V1.setABC(1, 2, 3);
129     V2.setABC(1, 2, 4);
130     cout<<V1.getV()<<endl;
131     if (judge(V1,V2)==1)
132     {
133         cout << "相等" << endl;
134     }
135     else
136     {
137         cout << "不等" << endl;
138     }
139     system("pause");
140     return;
141 }

 

posted @ 2017-03-29 17:34  Shaine  阅读(167)  评论(0)    收藏  举报