2576

/*
动态规划
*/

// include file
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <cctype>
#include <ctime>

#include <iostream>
#include <sstream>
#include <fstream>
#include <iomanip>
#include <bitset>

#include <algorithm>
#include <string>
#include <vector>
#include <queue>
#include <set>
#include <list>
#include <functional>

using namespace std;

// typedef
typedef long long LL;
typedef unsigned long long ULL;

// 
#define read freopen("in.txt","r",stdin)
#define write freopen("out.txt","w",stdout)
#define FORi(a,b,c) for(int i=(a);i<(b);i+=c)
#define FORj(a,b,c) for(int j=(a);j<(b);j+=c)
#define FORk(a,b,c) for(int k=(a);k<(b);k+=c)
#define FORp(a,b,c) for(int p=(a);p<(b);p+=c)
#define FORii(a,b,c) for(int ii=(a);ii<(b);ii+=c)
#define FORjj(a,b,c) for(int jj=(a);jj<(b);jj+=c)
#define FORkk(a,b,c) for(int kk=(a);kk<(b);kk+=c)

#define FF(i,a)    for(int i=0;i<(a);i++)
#define FFD(i,a)   for(int i=(a)-1;i>=0;i--)

#define Z(a) (a<<1)
#define Y(a) (a>>1)

const double eps = 1e-6;
const double INFf = 1e10;
const int INFi = 1000000000;
const double Pi = acos(-1.0);

template<class T> inline T sqr(T a){return a*a;}
template<class T> inline T TMAX(T x,T y)
{
	if(x>y) return x;
	return y;
}
template<class T> inline T TMIN(T x,T y)
{
	if(x<y) return x;
	return y;
}
template<class T> inline void SWAP(T &x,T &y)
{
	T t = x;
	x = y;
	y = t;
}
template<class T> inline T MMAX(T x,T y,T z)
{
	return TMAX(TMAX(x,y),z);
}


// code begin

bool f[2][102][22501]; // i个人选j个人是否能否到达权w  f[i][j][k] f[i-1][j'][k']
int N;
int G[110];
int main()
{
	read;
	write;
	int sum,Max,num;
	while(scanf("%d",&N)!=-1)
	{
		sum = 0;
		FORi(1,N+1,1)
		{
			scanf("%d",G+i);
			sum += G[i];
		}

		memset(f,0,sizeof(f));
		Max = sum/2;
		num = N/2;
		
		for(int i=1;i<=N;i++)
		{
			for(int j=0;j<=num+1;j++)
			{
				for(int k=0;k<=Max;k++)
				{
					f[i%2][j][k] |= f[(i-1)%2][j][k];
					if(j>=1&&k>=G[i]) f[i%2][j][k] |= f[(i-1)%2][j-1][k-G[i]];
				}
			}
			f[i%2][1][G[i]] = true;
		}

		int ans = 0 ;
		for(int i=Max;i>=0;i--)
		{
			if(f[N%2][num][i])
			{
				ans = i;
				break;
			}
		}
		if(N&1)
			for(int i=Max;i>=0;i--)
			{
				if(f[N%2][num+1][i])
				{
					if(i>ans)
					{
						ans = i;
					}
					break;
				}
			}

		printf("%d %d\n",ans,sum-ans);
	}
	return 0;
}

posted @ 2011-04-01 20:01  AC2012  阅读(134)  评论(0编辑  收藏  举报