实验4
1.实验任务1
task1.py
实验代码:
print(sum) sum = 42 print(sum) def inc(n): sum = n + 1 print(sum) return(sum) sum = inc(7) + inc(7) print(sum)
实验结果截图:

实验总结:
不是同一个对象的名称,line1 是建立一个sum函数, line3 对象是line2, line7作用域是line5到line8, line11作用对象是line10
2.实验任务2
task2_1.py
实验代码:
def func1(a, b, c, d, e, f): return [a,b,c,d,e,f] def func2(a, b, c,*, d, e, f): return [a,b,c,d,e,f] def func3(a, b, c, /, d, e, f): return [a,b,c,d,e,f] print( func1(1,9,2,0,5,3) ) print( func1(a=1, b=9, c=2, d=0, e=5, f=3) ) print( func1(1,9,2, f=3, d=0, e=5) ) print( func2(11, 99, 22, d=0, e=55, f=33) ) print( func2(a=11, b=99, c=22, d=0, e=55, f=33) ) print( func3(111, 999, 222, 0, 555, 333) ) print( func3(111, 999, 222, d=0, e=555, f=333) )
实验结果截图:

line33后增加 print( func2(11, 99, 22, 0, 55, 33) ) 后实验结果截图:

line38后增加 print( func3(a=111, b=999, c=222, 0, 555, 333) ) 后实验结果截图:

task2_2.py
实验代码:
list1 = [1, 9, 8, 4] print( sorted(list1) ) print( sorted(list1, reverse=True) ) print( sorted(list1, True) )
实验结果截图:

实验结论:
python内置函数sorted()中,参数reverse的传递方式必须使用关键字传递
task2_3.py
实验代码:
def func(a, b, c, / , *, d, e, f): return( [a,b,c,d,e,f] ) print( func(1, 2, 3, d=4, e=5, f=6) )
实验结果截图:

3.实验任务3
task3.py
实验代码:
def solve(a, b, c): delta = b*b - 4*a*c delta_sqrt = abs(delta)**0.5 p1 = -b/2/a p2 = delta_sqrt/2/a if delta >= 0: root1 = p1 + p2 root2 = p1 - p2 else: root1 = complex(p1, p2) root2 = complex(p1, -p2) return root1, root2 while True: try: t = input('输入一元二次方程系数a b c,或者,输入#结束;') if t == '#': print('结束计算,退出') break a, b, c = map(float, t.split()) if a == 0: raise ValueError('a = 0,不是一元二次方程') except ValueError as e: print(repr(e)) print() except: print('有其他错误发生\n') else: root1, root2 = solve(a, b, c) print(f'root1 = {root1:.2f}, root2 = {root2:.2f}') print()
实验结果截图:

在line23前增加 print(solve.__doc__) 后实验结果截图:

实验结果:
未被打印出
4.实验任务4
task4.py
实验代码:
def list_generator(a,b,c=1): lst = [] while a<=b: lst.append(a) a += c return lst list1 = list_generator(-5, 5) print(list1) list2 = list_generator(-5, 5, 2) print(list2) list3 = list_generator(1, 5, 0.5) print(list3)
实验结果截图:

5.实验任务5
task5.py
实验代码:
def is_prime(x): if x < 2: return False else: for i in range(2, x): if x % i == 0: return False break else: return True x = [] for i in range(2, 21): if is_prime(i): x.append(i) else: continue for j in range(2, 21, 2): for a in x: if (j-a) in x and a <= (j-a): print(f'{j} = {a} + {j-a}') else: continue
实验结果截图:

6.实验任务6
task6.py
实验代码:
def encoder(n): ls = list(n) for i in range(len(ls)): if 'a' <= ls[i].lower() <= 'u': ls[i] = chr(ord(ls[i]) + 5) elif 'v'<=ls[i].lower()<='z': ls[i] = chr(ord(ls[i]) - 21) else: pass return ''.join(ls) def decoder(n): ls = list(n) for i in range(len(ls)): if 'f' <= ls[i].lower() <= 'z': ls[i] = chr(ord(ls[i]) - 5) elif 'a'<=ls[i].lower()<='e': ls[i] = chr(ord(ls[i]) + 21) else: pass return ''.join(ls) text = input('输入英文文本: ') encoded_text = encoder(text) print('编码后的文本: ', encoded_text) decoded_text = decoder(encoded_text) print('对编码后的文本解码: ', decoded_text)
实验结果截图:

7.实验任务7
task7.py
实验代码:
# collatz函数定义 def collatz(n): n_list.append(n) while True: if n % 2 == 0 and n != 0: collatz(n // 2) elif (n + 1) % 2 == 0 and n != 1: collatz(n * 3 + 1) elif n == 1: print(n_list) break # 自定义异常 class Error(Exception): def __init__(self,n): self.n = n def __str__(self): print('Error: must be a positive integer') # 主题代码逻辑 try: n_list = [] n = input('输入一个正整数:') if n.isdigit() == False: raise Error(n) elif int(n) <= 0: raise Error(n) else: collatz(int(n)) except Error: print('Error: must be a positive integer')
实验结果截图:

8.实验任务8
task8.py
实验代码:
# 函数func()定义 def func(n): if n == 1: ans = 2 - 1 else: ans = 2 * func(n-1) +1 n -= 1 return ans # while True: x = input() if x == '#': print('计算结束') break n = int(x) ans = func(n) print(f'n = {n}, ans = {ans}')
实验结果截图:

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