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Problem Description N (1 ≤ N ≤ 100) cows, conveniently numbered 1..N, are participating in a programming contest. As we all know, some cows code bette 阅读全文
摘要:
判断回文数 代码 include using namespace std; int main() { int n; cin n; //输入一个整数 int ver = 0; //用来存储翻转后的数 int t = n; //用来记住n while (t 0) { //把n翻转 ver = ver 1 阅读全文
摘要:
#include using namespace std; int rand(int m, int n) { static int r; //默认初始值为0 do { r = (25173 * r + 13849) % 65536; } while (r = n); return r; } void add(int,... 阅读全文