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Form传递

Posted on 2009-04-15 11:39  緗灵  阅读(143)  评论(0)    收藏  举报

从一个页面A传到另一个页面B:

A:<asp:ImageButton ID="btnYulan" runat="server" ImageUrl="../images/yulan.gif"        PostBackUrl="B.aspx"   />

B:lblbiaoti.Text = Request.Form["txtbiaoti"].ToString();

      lblxiaoqu.Text = (PreviousPage.FindControl("txtloupanmc") as TextBox).Text;

      lblquyu.Text = (PreviousPage.FindControl("ddlquyu") as DropDownList).SelectedItem.Text;

      lblzhongjief.Text = (PreviousPage.FindControl("ddlzjf") as RadioButtonList).SelectedItem.Text;

      如果A页面里是HTML标签则:B页面 using System.Web.UI.HtmlControls;

      lblxiaoqu.Text = (PreviousPage.FindControl("txt_loupanmc") as HtmlInputText).Value;

      lbljiaotongqk.Text = (PreviousPage.FindControl("txt_jiaotongqk") as HtmlTextArea).Value;