摘要:
1斐波拉契数列前10个 #!/binbash#declare A=0declare B=1for ((i=1;i<6;i++)); do let A+=B printf "%-5s" $A let B+=A printf "%-5s" $Bdone printf "\n" 2、添加用户 ,并且询问是 阅读全文
posted @ 2018-07-21 16:36
坚定的眼神
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摘要:
1斐波拉契数列前10个 #!/binbash#declare A=0declare B=1for ((i=1;i<6;i++)); do let A+=B printf "%-5s" $A let B+=A printf "%-5s" $Bdone printf "\n" 2、添加用户 ,并且询问是 阅读全文
posted @ 2018-07-21 16:36
坚定的眼神
阅读(278)
评论(0)
推荐(0)
|