时间的表示

 dnDateTime = dotNetObject "System.DateTime" 1972 03 08 18 30 0
  
  -- prints "8/03/1972 6:30:00 PM" -- Australian
  format "%\n" (dnDateTime.toString())

 

DateTime = dotNetClass "System.DateTime"
date = DateTime.Parse "8/03/1972 6:30:00 PM"
print (date.ToString())

posted on 2011-10-08 19:40  盖天00  阅读(216)  评论(0)    收藏  举报

导航