Ajax简单的请求数据以表格的形式渲染到页面 

<!DOCTYPE html>
<html>

    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
        <title>长安汽车</title>
        <meta name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=1.0" />
        <meta name="description" content="">
        <meta name="keywords" content="">
        <script src="https://cdn.bootcss.com/jquery/2.1.2/jquery.min.js"></script>
        <script src="https://img.huiyiguanjia.com/CDNFile/layer/layer-v3.1.1/layer/layer.js"></script>
    </head>
    <body>
        <div class="main">
            <a onclick="lala()">点击我</a>
            <table id="table" border="1">

            </table>
        </div>
    </body>
</html>

<script type="text/javascript">
    function lala() {
        $.ajax({
            type: "get",
            url: "http://www.sghc.top:8081/api/Values/list",
            dataType: "json",
            error: function(data) {
                alert("连接超时");
            },
            success: function(data) {
                console.log(data)
                console.log(data.data[0].key);
                console.log(typeof(data.data[0].mimeType));
                var dataResult = data.data

                if (data.code == 200) {
                    $("#table").html("<tr><td>名称</td><td>图片</td></tr>");
                    for (var i = 0; i < dataResult.length; i++) {
                        var stingPic = dataResult[i].mimeType;
                        if(stingPic=="image/jpeg"){
                            $("#table").append("<tr><td>" + dataResult[i].key +
                                "</td><td>" + dataResult[i].mimeType +
                                "</td><tr>")
                        }

                    };

                }

            }
        });
    }
</script>

下图是师傅简化代码后的写法：

posted @ 2019-08-16 14:20  夏小夏吖  阅读(5092)  评论(0)  编辑  收藏  举报