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(转)get caller function name in called function at runtime

如题,想搞个这功能,增强failmalloc,不知道能否解决问题,有时间搞下,后续会跟进报道进展~—_—~

http://www.quora.com/C-programming-language/Is-there-a-way-to-print-the-name-of-the-calling-function-in-C-without-passing-it-as-an-argument

Although it's not very efficient and will affect your program's timing, one way is to compile your program with its symbol table (gcc -g ...), call the gcc function __builtin_return_address() as described by Kalyan and then call addr2line externally to decode it.  Alternatively, you could probably incorporate the functionality of addr2line directly into your program to provide this natively.

Example:

gcc -g -o print_caller print_caller.c
./print_caller 
f1
print_caller.c:28

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/* print_caller.c */
 
#include <stdio.h>
 
void
print_function(void *p) {
    char cmd[128];
    FILE *fp;
 
    snprintf(cmd, sizeof(cmd), "addr2line -e %s -f %p", "print_caller", p);
    fp = popen(cmd, "r");
    if (fp) {
        char buf[128];
        while (fgets(buf, sizeof(buf), fp)) {
            printf("%s", buf); 
        }
    }
}
 
void
f2(void) {
    print_function(__builtin_return_address(0));
}
 
void
f1(void) {
    f2();
}
 
int
main(int argc, char *argv[]) {
    f1();
    return(0);
}

As far as I think I know, I don't think there is a macro like __FUNCTI qrablurexp ON__ to directly print the caller function.

However, there are some GCC extensions to print the return address of the current function, caller function etc to some levels. So, from the returned 'return address' with a 'level' of 1, you should be able to find out the caller.

Refer to:
void * __builtin_return_address( unsigned int level ); [1]



References:
1. http://gcc.gnu.org/onlinedocs/gc...

posted @ 2012-08-08 23:04  europelee  阅读(595)  评论(0编辑  收藏