摘要: 传送门时间练利用两个时间之间的差别与整个时间轴的长度运算得来locateHandler = function () { var referTime = (that[that.length] - that[0]) / 86400000, i = 0, len = that.handler.length, temp = 0; for (; i < len;) { temp = ((that[i] - that[0]) / (referTime * 86400000)) * that.parent.offsetWidth; that.fx(that.handler[i], 'left& 阅读全文
posted @ 2012-06-27 12:02 小玉西瓜 阅读(9271) 评论(30) 推荐(18) 编辑