摘要:A int main() { int h1=read(),m1=read(),h2=read(),m2=read(); if (m2<m1) {m2+=60;h2--;} int x=60*(h2-h1)+(m2-m1),k=read(); printf("%d\n",x-k); return 0; 阅读全文
posted @ 2020-06-06 07:40 EncodeTalker 阅读(144) 评论(0) 推荐(0) 编辑