实验6

t4

 

 1 #include <stdio.h>
 2 #define N 10
 3 
 4 typedef struct{
 5     char isbn[20];
 6     char name[80];
 7     char author[80];
 8     double sales_price;
 9     int sales_count;
10 }book;
11 
12 void output(book x[],int n);
13 void sort(book x[],int n);
14 double sales_amount(book x[],int n);
15 
16 int main(){
17     book x[N]={
18     {"978-7-5327-6082-4","门将之死","罗纳德.伦",42,51},
19     {"978-7-308-17047-5","自由与爱之地:入以色列记","云也退",49,30},
20     {"978-7-5404-9344-8","伦敦人","克莱格泰勒",68,27},
21     {"978-7-5447-5246-6","软件体的生命周期","特德姜",35,90},
22     {"978-7-5722-5475-8","芯片简史","汪波",74.9,49},
23     {"978-7-5133-5750-0","主机战争","布莱克.J.哈里斯",128,42},
24     {"978-7-2011-4617-1","世界尽头的咖啡馆","约翰·史崔勒基",22.5,44},
25     {"978-7-5133-5109-6","你好外星人","英国未来出版集团",118,42},
26     {"978-7-1155-0509-5","无穷的开始:世界进步的本源","戴维·多伊奇",37.5,55},
27     {"978-7-229-14156-1","源泉","安.兰德",84,59}
28     };
29     
30     printf("图书销量排名(按销售册数):\n");
31     sort(x,N);
32     output(x,N);
33     
34     printf("\n图书销售总额:%.2f\n",sales_amount(x,N));
35     return 0;
36 }
37 
38 void output(book x[],int n){
39     int i;
40     printf("ISBN号\t\t\t书名\t\t\t  作者\t\t\t售价\t销售册数\n");
41     for(i=0;i<n;++i)
42     printf("%-20s%-30s%-20s%.1f\t%d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
43 }
44 
45 void sort(book x[],int n){
46     int i,j;
47     book t;
48     for(i=0;i<n;++i){
49         for(j=0;j<n-i;++j){
50             if(x[j].sales_count<x[j+1].sales_count){
51                 t=x[j+1];
52                 x[j+1]=x[j];
53                 x[j]=t;
54             }
55         }
56     }
57 }
58 
59 double sales_amount(book x[],int n){
60     int i;
61     double sum=0;
62     for(i=0;i<n;++i){
63         sum+=x[i].sales_count*x[i].sales_price;
64     }
65     return sum;
66 }
4

 

t5

 

  1 #include<stdio.h>
  2 
  3 typedef struct{
  4     int year;
  5     int month;
  6     int day;
  7 }Date;
  8 
  9 void input(Date *pd);
 10 int day_of_year(Date d);
 11 int compare_dates(Date d1,Date d2);
 12 
 13 void test1(){
 14     Date d;
 15     int i;
 16     
 17     printf("输入日期:(以形如2025-06-01这样的形式输入)\n");
 18     for(i=0;i<3;++i){
 19         input(&d);
 20         printf("%d-%02d-%02d是这一年中第%d天\n\n",d.year,d.month,d.day,day_of_year(d));
 21     }
 22 }
 23 
 24 void test2(){
 25     Date Alice_birth,Bob_birth;
 26     int i;
 27     int ans;
 28     
 29     printf("输入Alice和Bob出生日期:(以形如2025-06-01这样的形式输入)\n");
 30     for(i=0;i<3;++i){
 31         input(&Alice_birth);
 32         input(&Bob_birth);
 33         ans=compare_dates(Alice_birth,Bob_birth);
 34         
 35         if(ans==0)
 36         printf("Alice和Bob一样大\n\n");
 37         else if(ans==-1)
 38         printf("Alice比Bob大\n\n");
 39         else
 40         printf("Alice比Bob小\n\n");
 41     }
 42 }
 43 
 44 int main(){
 45     printf("测试1:输入日期,打印输出这是一年中第多少天\n");
 46     test1();
 47     
 48     printf("\n测试2:两个人年龄大小关系\n");
 49     test2();
 50 }
 51 
 52 void input(Date *pd){
 53     scanf("%d-%d-%d",&(pd->year),&(pd->month),&(pd->day));
 54 }
 55 
 56 int day_of_year(Date d){
 57     int a,dan=0,shuang=0;
 58     if((d.year%4==0&&d.year%100!=0)||d.year%400==0){
 59         if(d.month==1)
 60         a=d.day;
 61         else if(d.month==2)
 62         a=31+d.day;
 63         else{
 64             if(d.month%2==0){
 65             dan=d.month/2;
 66             shuang=d.month/2-2;
 67             a=31*dan+30*shuang+29+d.day;}
 68             else{
 69             dan=d.month/2;
 70             shuang=d.month/2-1;
 71             a=31*dan+30*shuang+29+d.day;
 72             }
 73         }
 74         
 75     }
 76     else{
 77         if(d.month==1)
 78         a=d.day;
 79         else if(d.month==2)
 80         a=31+d.day;
 81         else{
 82             if(d.month%2==0){
 83             dan=d.month/2;
 84             shuang=d.month/2-2;
 85             a=31*dan+30*shuang+28+d.day;}
 86             else{
 87             dan=d.month/2;
 88             shuang=d.month/2-1;
 89             a=31*dan+30*shuang+28+d.day;
 90     }
 91     
 92 }return a;
 93 }
 94 }
 95 
 96 int compare_dates(Date d1,Date d2){
 97     int i,a1,a2;
 98     a1=day_of_year(d1);
 99     a2=day_of_year(d2);
100     if(d1.year==d2.year){
101     if(a1<a2)
102     i=-1;
103     else if(a1>a2)
104     i=1;
105     else
106     i=0;}
107     else{
108         if(d1.year<d2.year)
109         i=-1;
110         else 
111         i=1;
112     }
113     return i;
114 }
5

 

t6

 

 1 #include<stdio.h>
 2 #include<string.h>
 3 
 4 enum role{admin,student,teacher};
 5 
 6 typedef struct{
 7     char username[20];
 8     char password[20];
 9     enum role type;
10 }account;
11 
12 void output(account x[],int n);
13 
14 int main(){
15     account x[]={
16     {"A1001","123456",student},
17     {"A1002","123abcdef",student},
18     {"A1009","Xyz12121",student},
19     {"X1009","9213071x",admin},
20     {"c11553","129dfg32k",teacher},
21     {"X3005","921kfmg917",student}};
22     int n;
23     n=sizeof(x)/sizeof(account);
24     output(x,n);
25     
26     return 0;
27 }
28 
29 void output(account x[],int n){
30     int i,j;
31     for(i=0;i<n;++i){
32         printf("%-20s",x[i].username);
33         for(j=0;j<strlen(x[i].password);++j)
34         printf("*");
35         printf("\t\t\t");
36         switch(x[i].type){
37             case (admin):printf("admin\n");break;
38             case (student):printf("student\n");break;
39             case (teacher):printf("teacher\n");break;
40             default:break;
41         }
42     }
43 }
6

 

t7

 1 #include<stdio.h>
 2 #include<string.h>
 3 
 4 typedef struct{
 5     char name[20];
 6     char phone[12];
 7     int vip;
 8 }contact;
 9 
10 void set_vip_contact(contact x[],int n,char name[]);
11 void output(contact x[],int n);
12 void display(contact x[],int n);
13 
14 #define N 10
15 int main(){
16     contact list[N]={
17     {"刘一", "15510846604", 0},
18     {"陈二", "18038747351", 0},
19     {"张三", "18853253914", 0},
20     {"李四", "13230584477", 0},
21     {"王五", "15547571923", 0},
22     {"赵六", "18856659351", 0},
23     {"周七", "17705843215", 0},
24     {"孙八", "15552933732", 0},
25     {"吴九", "18077702405", 0},
26     {"郑十", "18820725036", 0}};
27     
28     int vip_cnt,i;
29     char name[20];
30     
31     printf("显示原始通讯录信息:\n");
32     output(list,N) ;
33     
34     printf("输入要设置的紧急联系人个数:");
35     scanf("%d",&vip_cnt);
36     printf("输入%d个紧急联系人姓名:\n",vip_cnt);
37     for(i=0;i<vip_cnt;++i){
38         scanf("%s",name);
39         set_vip_contact(list,N,name);
40     }
41     
42     printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
43     display(list,N);
44     
45     return 0;
46 }
47 
48 void set_vip_contact(contact x[],int n,char name[]){
49     int i,j;
50     for(i=0;i<n;++i){
51         if(strcmp(x[i].name,name)==0)
52             x[i].vip=1;
53         }
54     
55 }
56 
57 void display(contact x[],int n){
58     int i,j;
59     contact t;
60     for(i=0;i<n-1;++i){
61         for(j=0;j<n-1-i;++j){
62             if(x[j].vip<x[j+1].vip){
63             t=x[j];
64             x[j]=x[j+1];
65             x[j+1]=t;    
66             }
67             if(x[j].vip==0)
68             if(strcmp(x[j].name,x[j+1].name)>0){
69                 t=x[j];
70                 x[j]=x[j+1];
71                 x[j+1]=t;
72                 }
73                 
74             }
75         }
76     
77     
78     for(i=0;i<n;++i){
79         printf("%-10s%-15s",x[i].name,x[i].phone);
80         if(x[i].vip)
81         printf("%5s","*");
82         printf("\n");
83     }
84 }
85 
86 void output(contact x[],int n){
87     int i;
88     
89     for(i=0;i<n;++i){
90         printf("%-10s%-15s",x[i].name,x[i].phone);
91         if(x[i].vip)
92         printf("%5s","*");
93         printf("\n");
94     }
95 }
7

 

posted @ 2025-06-07 23:03  diaojiayi  阅读(2)  评论(0)    收藏  举报