机器学习 — 推荐系统

机器学习 — 推荐系统

 

作者:大树 深圳
更新时间:2018.02.08

email:59888745@qq.com

说明:因内容较多,会不断更新 xxx学习总结;

回主目录:2017 年学习记录和总结

 

技术架构

1.对内容数据,用户数据,行为数据,进行数据处理,格式化,清洗,归并等;
2.根据业务规则建立推荐系统,内容画像,用户画像,行为画像;
3.根据建立的各种画像,进行相关推荐,个性化推荐,相关推荐,热门推荐等;
4.推荐形式有,相似度推荐,相关内容推荐,好友推荐,排名推荐.

 

核心算法是计算相似度,欧几里得距离公式,排名等。

 

 

机器学习 — 推荐系统

dennychen in shenzhen

1提供推荐

1。协作过里

2。搜集偏好

3。寻找相近的用户

4。推荐物品,根据用户相似度推荐,根据物品排名推荐

5。匹配商品

6。构建推荐系统

7。基于物品的过里

8。使用数据集

9。基于用户进行过里还是基于物品进行过里

2。计算用户相似度, 欧几里得距离 pearson相关度

3。计算两个人的相似度,本来是推荐平均评分较高的作品,考虑到两个人的爱好相似程度,对评分根据相似度进行加权平均.

In [ ]:
 
from math import sqrt

critics={'dennychen': {'Lady in the Water': 2.5, 'Snakes on a Plane': 3.5,
 'tomastang': 3.0, 'Superman Returns': 3.5, 'You, Me and Dupree': 2.5,
 'The Night Listener': 3.0},
'alexye': {'Lady in the Water': 3.0, 'Snakes on a Plane': 3.5,
 'Just My Luck': 1.5, 'Superman Returns': 5.0, 'The Night Listener': 3.0,
 'You, Me and Dupree': 3.5},
'Michaelzhou': {'Lady in the Water': 2.5, 'Snakes on a Plane': 3.0,
 'Superman Returns': 3.5, 'The Night Listener': 4.0},
'josephtcheng': {'Snakes on a Plane': 3.5, 'Just My Luck': 3.0,
 'The Night Listener': 4.5, 'Superman Returns': 4.0,
 'You, Me and Dupree': 2.5},
'antyonywang': {'Lady in the Water': 3.0, 'Snakes on a Plane': 4.0,
 'Just My Luck': 2.0, 'Superman Returns': 3.0, 'The Night Listener': 3.0,
 'You, Me and Dupree': 2.0},
'jackfan': {'Lady in the Water': 3.0, 'Snakes on a Plane': 4.0,
 'The Night Listener': 3.0, 'Superman Returns': 5.0, 'You, Me and Dupree': 3.5},
'Toby': {'Snakes on a Plane':4.5,'You, Me and Dupree':1.0,'Superman Returns':4.0}}

print(critics['dennychen']['Lady in the Water'])
print(critics['alexye']['Lady in the Water'])
# a ['Lady in the Water', 'Snakes on a Plane', 'Superman Returns', 'You, Me and Dupree', 'The Night Listener']
# sum_of_squares 3.5
In [37]:
import pandas as pd
from math import sqrt

critics={'dennychen': {'Lady in the Water': 2.5, 'Snakes on a Plane': 3.5,
 'tomastang': 3.0, 'Superman Returns': 3.5, 'You, Me and Dupree': 2.5,
 'The Night Listener': 3.0},
'alexye': {'Lady in the Water': 3.0, 'Snakes on a Plane': 3.5,
 'Just My Luck': 1.5, 'Superman Returns': 5.0, 'The Night Listener': 3.0,
 'You, Me and Dupree': 3.5},
'Michaelzhou': {'Lady in the Water': 2.5, 'Snakes on a Plane': 3.0,
 'Superman Returns': 3.5, 'The Night Listener': 4.0},
'josephtcheng': {'Snakes on a Plane': 3.5, 'Just My Luck': 3.0,
 'The Night Listener': 4.5, 'Superman Returns': 4.0,
 'You, Me and Dupree': 2.5},
'antyonywang': {'Lady in the Water': 3.0, 'Snakes on a Plane': 4.0,
 'Just My Luck': 2.0, 'Superman Returns': 3.0, 'The Night Listener': 3.0,
 'You, Me and Dupree': 2.0},
'jackfan': {'Lady in the Water': 3.0, 'Snakes on a Plane': 4.0,
 'The Night Listener': 3.0, 'Superman Returns': 5.0, 'You, Me and Dupree': 3.5},
'Toby': {'Snakes on a Plane':4.5,'You, Me and Dupree':1.0,'Superman Returns':4.0}}

 
# 欧几里得距离评价,评价2这之间的相似度,值越接近1,相似度越高
def sim_distance(prefs, person1, person2):
    si = {}
    for item in prefs[person1]:
        if item in prefs[person2]:
            si[item] = 1
            
    if len(si) == 0:
        return 0
    a =[item  for item in prefs[person1] if item in prefs[person2]]
    print('a',a)
    sum_of_squares = sum([pow(prefs[person1][item] - prefs[person2][item], 2) for item in prefs[person1] if item in prefs[person2]])
    print('sum_of_squares',sum_of_squares)
    return 1 / (1 + sqrt(sum_of_squares))

print(sim_distance(critics, 'dennychen', 'Michaelzhou'))
print(sim_distance(critics, 'dennychen', 'alexye'))
 
a ['Lady in the Water', 'Snakes on a Plane', 'Superman Returns', 'The Night Listener']
sum_of_squares 1.25
0.4721359549995794
a ['Lady in the Water', 'Snakes on a Plane', 'Superman Returns', 'You, Me and Dupree', 'The Night Listener']
sum_of_squares 3.5
0.3483314773547883
In [38]:
sim_pearson(critics, 'dennychen', 'alexye')
Out[38]:
0.6085806194501843
In [ ]:
 
In [32]:
import pandas as pd
from math import sqrt

critics={'dennychen': {'Lady in the Water': 2.5, 'Snakes on a Plane': 3.5,
 'tomastang': 3.0, 'Superman Returns': 3.5, 'You, Me and Dupree': 2.5,
 'The Night Listener': 3.0},
'alexye': {'Lady in the Water': 3.0, 'Snakes on a Plane': 3.5,
 'Just My Luck': 1.5, 'Superman Returns': 5.0, 'The Night Listener': 3.0,
 'You, Me and Dupree': 3.5},
'Michaelzhou': {'Lady in the Water': 2.5, 'Snakes on a Plane': 3.0,
 'Superman Returns': 3.5, 'The Night Listener': 4.0},
'josephtcheng': {'Snakes on a Plane': 3.5, 'Just My Luck': 3.0,
 'The Night Listener': 4.5, 'Superman Returns': 4.0,
 'You, Me and Dupree': 2.5},
'antyonywang': {'Lady in the Water': 3.0, 'Snakes on a Plane': 4.0,
 'Just My Luck': 2.0, 'Superman Returns': 3.0, 'The Night Listener': 3.0,
 'You, Me and Dupree': 2.0},
'jackfan': {'Lady in the Water': 3.0, 'Snakes on a Plane': 4.0,
 'The Night Listener': 3.0, 'Superman Returns': 5.0, 'You, Me and Dupree': 3.5},
'Toby': {'Snakes on a Plane':4.5,'You, Me and Dupree':1.0,'Superman Returns':4.0}}

 
# 欧几里得距离评价,评价2这之间的相似度,值越接近1,相似度越高
def sim_distance(prefs, person1, person2):
    si = {}
    for item in prefs[person1]:
        if item in prefs[person2]:
            si[item] = 1
            
    if len(si) == 0:
        return 0
    a =[item  for item in prefs[person1] if item in prefs[person2]]
    print('a',a)
    sum_of_squares = sum([pow(prefs[person1][item] - prefs[person2][item], 2) for item in prefs[person1] if item in prefs[person2]])
    print('sum_of_squares',sum_of_squares)
    return 1 / (1 + sqrt(sum_of_squares))

# 皮尔逊相关度评价
def sim_pearson(prefs, person1, person2):
    # 得到两者评价过的相同商品
    si = {}
    for item in prefs[person1]:
        if item in  prefs[person2]:
            si[item] = 1
   
    n = len(si)
    # 如果两个用户之间没有相似之处则返回1
    if n == 0:
        return 1
    
    # 对各自的所有偏好求和
    sum1 = sum([prefs[person1][item] for item in si])
    sum2 = sum([prefs[person2][item] for item in si])
    
    # 求各自的平方和
    sum1_square = sum([pow(prefs[person1][item], 2) for item in si])
    sum2_square = sum([pow(prefs[person2][item], 2) for item in si])
    
    # 求各自的乘积的平方
    sum_square = sum([prefs[person1][item] * prefs[person2][item] for item in si])
    
    # 计算pearson相关系数
    den = sqrt((sum1_square - pow(sum1, 2) / n) * (sum2_square - pow(sum2, 2) / n))
    if den == 0:
        return 0

    return (sum_square - (sum1 * sum2/n)) / den



def topMatches(prefs, person, n = 5, simlarity = sim_pearson):
    scores = [(simlarity(prefs, person, other), other) for other in prefs if other != person]
    
    # 对列表进行排序,评价高者排在前面
    scores.sort()
    print('scores:',scores)
    scores.reverse()
    # 取指定个数的(不需要判断n的大小,因为python中的元组可以接受正、负不在范围内的index)
    return scores[0:n]



# 利用其他所有人的加权平均给用户推荐
def get_recommendations(prefs, person, similarity=sim_pearson):
    # 其他用户对某个电影的评分加权之后的总和
    totals = {}
    # 其他用户的相似度之和
    sim_sums = {}
    for other in prefs:
        # 不和自己比较
        if other == person:
            continue
        
        # 求出相似度
        sim = similarity(prefs, person, other)
        # 忽略相似度小于等于情况0的
        if sim <= 0:
            continue
        
        # 获取other所有的评价过的电影评分的加权值
        for item in prefs[other]:
            # 只推荐用户没看过的电影
            if item not in prefs[person] or prefs[person][item] == 0:
                #print item
                # 设置默认值
                totals.setdefault(item, 0)
                # 求出该电影的加权之后的分数之和
                totals[item] += prefs[other][item] * sim
                # 求出各个用户的相似度之和
                sim_sums.setdefault(item, 0)
                sim_sums[item] += sim
        

    # 对于加权之后的分数之和取平均值
    rankings = [(total / sim_sums[item], item) for item, total in totals.items()]

    # 返回经过排序之后的列表
    rankings.sort()
    rankings.reverse()
    return rankings

sim_distance(critics, 'dennychen', 'Michaelzhou')
# sim_pearson(critics, 'Lisa Rose', 'Gene Seymour')
topMatches(critics, 'dennychen', n = 3)

# get_recommendations(critics, 'Toby')
# get_recommendations(critics, 'Toby', similarity=sim_distance)
 
a ['Lady in the Water', 'Snakes on a Plane', 'Superman Returns', 'The Night Listener']
sum_of_squares 1.25
scores: [(0.40451991747794525, 'Michaelzhou'), (0.5606119105813882, 'josephtcheng'), (0.6085806194501843, 'alexye'), (0.7071067811865475, 'antyonywang'), (0.7470178808339965, 'jackfan'), (0.9912407071619299, 'Toby')]
Out[32]:
[(0.9912407071619299, 'Toby'),
 (0.7470178808339965, 'jackfan'),
 (0.7071067811865475, 'antyonywang')]
In [ ]:
 
posted @ 2018-02-09 15:45  大树2  阅读(508)  评论(0编辑  收藏  举报