摘要:
#includeint p[10001];void chart(){ p[0] = 0; for (int i = 1; i i) break; } if (i == sum) p[i] = p[i - 1... 阅读全文
posted @ 2014-08-04 12:25
Barcelona&&cl
阅读(140)
评论(0)
推荐(0)
|
Bacelona
心系诺坎普
|
|
|