实验1

task2.c
 1 #include <stdio.h>

int main()
{
    double a, b, c;

    scanf("%lf%lf%lf", &a, &b, &c);

    if((a+b>c)&&(b+c>a)&&(a+c>b))
        printf("能构成三角形\n");
    else
        printf("不能构成三角形\n");

    return 0;

}

 

task1.c

//打印一个字符小人

#include <stdio.h>
int main()
{
    printf(" O     O\n");
    printf("<H>   <H>\n");
    printf("I I   I I\n");

    return 0;
}

 

task3.c

#include <stdio.h>
int main()
{
    char ans1, ans2; 

    printf("每次课前认真预习、课后及时复习了没?  ");
    ans1 = getchar(); 

    getchar(); 

    printf("\n动手敲代码实践了没?  ");
    ans2 = getchar();

    if (ans1 == 'y'||ans2 =='Y') 
    printf("\n罗马不是一天建成的, 继续保持哦:)\n");
    else
    printf("\n罗马不是一天毁灭的, 我们来建设吧\n");
    return 0;
}

 

task4.c

#include <stdio.h>

int main()
{
    double x, y;
    char c1, c2, c3;
    int a1, a2, a3;

    scanf("%d%d%d", &a1, &a2, &a3);
    printf("a1 = %d, a2 = %d, a3 = %d\n", a1, a2, a3);

    scanf("%c%c%c", &c1, &c2, &c3);
    printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);

    scanf("%lf,%lf", &x, &y);
    printf("x = %f, y = %lf\n",x, y);

    return 0;

#include <stdio.h>
int main()
{
    int year;

    int seconds_in_year = 365 * 24 * 60 * 60;
     long long total_seconds = 1000000000;

     double years = (double)total_seconds / seconds_in_year;
     year = (int)(years + 0.5);
    printf("10亿秒约等于%d年\n", year);
    return 0;
}

 

task6.c

#include <stdio.h>
#include <math.h>
int main()
{
    double x, ans;
    
    scanf("%lf", &x);
    ans = pow(x, 365);
    printf("%.2f的365次方: %.2f\n", x, ans);

    return 0;
}

#include <stdio.h>
int main() {
    double C, F;
    // 多组输入，直到按下ctrl+z终止
    while (scanf("%lf", &C) != EOF) {
        // 计算华氏温度：F = 9/5*C + 32
        F = 1.8 * C + 32;
        // 保留两位小数输出
        printf("%.2f\n", F);
    }
    return 0;
}

 

task8.c

#include <stdio.h>
#include <math.h>
int main() {
    double a, b, c, s, area;
    
    while (scanf("%lf %lf %lf", &a, &b, &c) != EOF) {
        // 计算半周长 s
        s = (a + b + c) / 2;
        // 利用海伦公式计算面积
        area = sqrt(s * (s - a) * (s - b) * (s - c));
        // 保留三位小数输出面积
        printf("%.3f\n", area);
    }
    return 0;
}