摘要: 题面 观察原递推式, \(f_i=1\times f_{i-1}+0\times f_{i-2}+1\times f_{i-3}\) , 所以 \[ \begin{aligned} f_i &= 1\times f_{i-1}+0\times f_{i-2}+1\times f_{i-3}, \\ 阅读全文
posted @ 2021-08-19 17:59 Chiimo 阅读(8) 评论(0) 推荐(0) 编辑