﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>博客园-普若伽门的黑白-最新评论</title><link>http://www.cnblogs.com/x116/CommentsRSS.aspx</link><description>十年磨一剑</description><language>zh-cn</language><pubDate>Sat, 19 Jul 2008 07:17:55 GMT</pubDate><lastBuildDate>Sat, 19 Jul 2008 07:17:55 GMT</lastBuildDate><generator>cnblogs</generator><item><title>re: Rails 2.0完整体验：Rolling with Rails 2.0 - The First Full Tutorial - Part 1(翻译)</title><link>http://www.cnblogs.com/x116/archive/2008/04/20/1035589.html#1162573</link><dc:creator>libing</dc:creator><author>libing</author><pubDate>Sun, 20 Apr 2008 08:11:00 GMT</pubDate><guid>http://www.cnblogs.com/x116/archive/2008/04/20/1035589.html#1162573</guid><description><![CDATA[写的不错 <br>受益了<br><br><div align=right><a style="text-decoration:none;" href="http://www.cnblogs.com/x116/" target="_blank">libing</a> 2008-04-20 16:11 <a href="http://www.cnblogs.com/x116/archive/2008/04/20/1035589.html#1162573#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: Rails 2.0完整体验：Rolling with Rails 2.0 - The First Full Tutorial - Part 1(翻译)</title><link>http://www.cnblogs.com/x116/archive/2008/03/26/1035589.html#1123768</link><dc:creator>givemelose</dc:creator><author>givemelose</author><pubDate>Wed, 26 Mar 2008 14:23:00 GMT</pubDate><guid>http://www.cnblogs.com/x116/archive/2008/03/26/1035589.html#1123768</guid><description><![CDATA[真的写的不错,受益非浅,希望能看到更多的好文章.<br><br><div align=right><a style="text-decoration:none;" href="http://www.cnblogs.com/x116/" target="_blank">givemelose</a> 2008-03-26 22:23 <a href="http://www.cnblogs.com/x116/archive/2008/03/26/1035589.html#1123768#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: C#写海盗分金算法</title><link>http://www.cnblogs.com/x116/archive/2008/02/17/1030746.html#1071533</link><dc:creator>普若伽门</dc:creator><author>普若伽门</author><pubDate>Sun, 17 Feb 2008 12:54:00 GMT</pubDate><guid>http://www.cnblogs.com/x116/archive/2008/02/17/1030746.html#1071533</guid><description><![CDATA[后来仔细思索，确实不对，对于大于等于半数情况时的方案应该是{1-5}98 0 1 0 1;<br>倒推过来<br>第四个人的方案 ： 100 0   ，必定通过<br>第三个   ：    99  0  1，必定通过<br>第二个人 ： 99  0  1   0，必定通过<br><br><div align=right><a style="text-decoration:none;" href="http://www.cnblogs.com/x116/" target="_blank">普若伽门</a> 2008-02-17 20:54 <a href="http://www.cnblogs.com/x116/archive/2008/02/17/1030746.html#1071533#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: C#写海盗分金算法</title><link>http://www.cnblogs.com/x116/archive/2008/02/17/1030746.html#1071505</link><dc:creator>asfsfds</dc:creator><author>asfsfds</author><pubDate>Sun, 17 Feb 2008 12:21:00 GMT</pubDate><guid>http://www.cnblogs.com/x116/archive/2008/02/17/1030746.html#1071505</guid><description><![CDATA[楼主，{1-5} 98 1 1 0 0 这个恐怕是不行的，2号只得到1枚金币是不会同意1号的方案的，这样1号被扔入大海喂鲨鱼，2号可以得到更多的金币（99枚）。<br><br><div align=right><a style="text-decoration:none;" href="http://www.cnblogs.com/x116/" target="_blank">asfsfds</a> 2008-02-17 20:21 <a href="http://www.cnblogs.com/x116/archive/2008/02/17/1030746.html#1071505#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item></channel></rss>