﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>博客园-Simba &amp;&amp; Nala's Blog-最新评论</title><link>http://www.cnblogs.com/simba/CommentsRSS.aspx</link><description>栽种思想，成就行为；栽种行为，成就习惯；栽种习惯，成就性格；栽种性格，成就命运！</description><language>zh-cn</language><pubDate>Mon, 07 Jul 2008 10:55:27 GMT</pubDate><lastBuildDate>Mon, 07 Jul 2008 10:55:27 GMT</lastBuildDate><generator>cnblogs</generator><item><title>re: 自定义报表开发、使用手册</title><link>http://www.cnblogs.com/simba/archive/2008/04/02/1132362.html#1134028</link><dc:creator>鬼画符</dc:creator><author>鬼画符</author><pubDate>Wed, 02 Apr 2008 01:45:00 GMT</pubDate><guid>http://www.cnblogs.com/simba/archive/2008/04/02/1132362.html#1134028</guid><description><![CDATA[baidu限制图片连接了。<br>原贴在这里：<br><a href="http://hi.baidu.com/simbagu/blog/item/41d2ce1735c256054a90a711.html" target="_new">http://hi.baidu.com/simbagu/blog/item/41d2ce1735c256054a90a711.html</a><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnblogs.com/simba/" target="_blank">鬼画符</a> 2008-04-02 09:45 <a href="http://www.cnblogs.com/simba/archive/2008/04/02/1132362.html#1134028#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: 自定义报表开发、使用手册</title><link>http://www.cnblogs.com/simba/archive/2008/04/01/1132362.html#1133472</link><dc:creator>linger</dc:creator><author>linger</author><pubDate>Tue, 01 Apr 2008 13:09:00 GMT</pubDate><guid>http://www.cnblogs.com/simba/archive/2008/04/01/1132362.html#1133472</guid><description><![CDATA[嘿嘿～楼主～图片看不见<br><br><div align=right><a style="text-decoration:none;" href="http://www.cnblogs.com/simba/" target="_blank">linger</a> 2008-04-01 21:09 <a href="http://www.cnblogs.com/simba/archive/2008/04/01/1132362.html#1133472#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: 百度一道关于算法的面试题目</title><link>http://www.cnblogs.com/simba/archive/2007/09/19/565485.html#898184</link><dc:creator>chj</dc:creator><author>chj</author><pubDate>Wed, 19 Sep 2007 03:27:00 GMT</pubDate><guid>http://www.cnblogs.com/simba/archive/2007/09/19/565485.html#898184</guid><description><![CDATA[不需要这么复杂吧  用平面几何的知识就能解决的了  以时间t为横坐标  细木杠0cm处起点为坐标原点建立坐标轴，设定蚂蚁的轨道为 yi = ai + ki*t  ( i = 1,2,3,4,5 )  ( a1 = 3, a2 = 7, a3 = 11, a4 = 17, a5 = 23 )<br><br>容易证明以下结论：<br>蚂蚁全部离开木杠的时间 T = max { Ti}  ， ( i = 1,2,3,4,5 )<br>其中Ti 由以下算得：<br>如果ki &gt; 0 , 则Ti = 27 - ai.<br>如果ki &lt; 0,则Ti = ai.<br><br><div align=right><a style="text-decoration:none;" href="http://www.cnblogs.com/simba/" target="_blank">chj</a> 2007-09-19 11:27 <a href="http://www.cnblogs.com/simba/archive/2007/09/19/565485.html#898184#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item></channel></rss>