阳光男孩

string B = "abcd@@efg@@sdff;";

string C=abcde@efgasdfl@sdlfjs;

如果要分割C很容易，只需如此即可：

A = C.Split('@');

结果：

A[0] = "abcde";

A[1] = "efgasdfl";

A[2] = "sdlfjs"; 

如果要分割B呢?最简单的办法就是先把@@替换为单字符串了。 

A = B.Replace("@@","$").Split('$');

A[0] = "abcd";

A[1] = "efg";

      function isTime(str)

      {

        var a = str.match(/^(\d{1,2})(:)?(\d{1,2})\2(\d{1,2})$/);

        if (a == null) {alert('输入的参数不是时间格式'); return false;}

        if (a[1]>24 || a[3]>60 || a[4]>60)

        {

          alert("时间格式不对");

          return false

        }

        return true;

      }

  18.2 短日期，形如 (2003-12-05)

      function strDateTime(str)

      {

         var r = str.match(/^(\d{1,4})(-|\/)(\d{1,2})\2(\d{1,2})$/);

         if(r==null)return false;

         var d= new Date(r[1], r[3]-1, r[4]);

         return (d.getFullYear()==r[1]&&(d.getMonth()+1)==r[3]&&d.getDate()==r[4]);

      }

  18.3 长时间，形如 (2003-12-05 13:04:06)

      function strDateTime(str)

      {

        var reg = /^(\d{1,4})(-|\/)(\d{1,2})\2(\d{1,2}) (\d{1,2}):(\d{1,2}):(\d{1,2})$/;

        var r = str.match(reg);

        if(r==null)return false;

        var d= new Date(r[1], r[3]-1,r[4],r[5],r[6],r[7]);

        return (d.getFullYear()==r[1]&&(d.getMonth()+1)==r[3]&&d.getDate()==r[4]&&d.getHours()==r[5]&&d.getMinutes()==r[6]&&d.getSeconds()==r[7]);